Volume Calculator

Calculate volume of boxes, cylinders, spheres, and cones in multiple units.

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Quick Tip

Choose the shape: box, cylinder, sphere or cone.

About This Tool

Why use Volume Calculator?

Work out the volume of a box, cylinder, sphere or cone and see the result in litres, US gallons and cubic feet. A box is length × width × height, a cylinder is πr²h, a sphere is (4/3)πr³ and a cone is (1/3)πr²h.

A cylindrical tank 1 m across and 1.5 m tall holds π × 0.5² × 1.5 = 1.18 m³, which is 1,178 litres or 311 US gallons. Note that a cone holds exactly one third of the cylinder with the same base and height, which is a useful check on the result.

Key Benefits

Four shapes with capacity conversions

Geometric volume plus the litre and gallon figures you need for tanks and containers.

US gallons stated clearly

1 US gallon is 3.785 litres; the UK imperial gallon is 4.546 litres, so the two are not interchangeable.

Consistent with the area tools

Same shape choices and units as the area and square footage calculators, so measurements carry across.

How to use Volume Calculator

  1. 1

    Choose the shape: box, cylinder, sphere or cone.

  2. 2

    Select the unit you are measuring in.

  3. 3

    Enter the dimensions — radius and height for round shapes.

  4. 4

    Read the volume, plus litres, gallons and cubic feet for capacity planning.

Best use cases

Size a water tank, aquarium or pond.

Work out how much soil or gravel fills a raised bed.

Calculate shipping volume for a box.

Check volume questions in geometry homework.

Volume Calculator FAQs

What is the volume formula for a cylinder?

V = πr²h. For a radius of 0.5 m and height 2 m: π × 0.25 × 2 ≈ 1.571 m³, or 1,571 litres.

How many litres are in a cubic metre?

Exactly 1,000. A cubic foot is about 28.32 litres.

What is the volume of a sphere?

V = (4/3)πr³. A ball with a 10 cm radius holds (4/3) × π × 1,000 ≈ 4,189 cm³, or about 4.19 litres.

Why is a cone a third of a cylinder?

With the same base radius and height, the cone's formula is exactly (1/3)πr²h against the cylinder's πr²h — a result that comes from integrating the cross-sectional area.

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